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5x^2-95x-30=0
a = 5; b = -95; c = -30;
Δ = b2-4ac
Δ = -952-4·5·(-30)
Δ = 9625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9625}=\sqrt{25*385}=\sqrt{25}*\sqrt{385}=5\sqrt{385}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-5\sqrt{385}}{2*5}=\frac{95-5\sqrt{385}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+5\sqrt{385}}{2*5}=\frac{95+5\sqrt{385}}{10} $
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